Sagot :
x + y = 40
In terms of x:
x + y = 40
y = 40 - x
Let first number = x
second number = 40-x
product of the two numbers = 300
Equation
(x) (40-x) = 300
40x - x² = 300
Equate to zero:
-x² + 40x - 300 = 0
Solve by factoring:
-(x-10) (x-30) = 0
-x + 10 = 0 x - 30 = 0
- x = -10 x = 30
x = 10
The two numbers are:
If x = 10
Then the two numbers are:
first number x = 10
second number (40-10) = 30
If x = 30
Then the two numbers are:
first number = 30
second number (x-30) = 10
Even if interchanged, the two numbers are 10 and 30
To check:
10 + 30 = 40
(10) (30) = 300
In terms of x:
x + y = 40
y = 40 - x
Let first number = x
second number = 40-x
product of the two numbers = 300
Equation
(x) (40-x) = 300
40x - x² = 300
Equate to zero:
-x² + 40x - 300 = 0
Solve by factoring:
-(x-10) (x-30) = 0
-x + 10 = 0 x - 30 = 0
- x = -10 x = 30
x = 10
The two numbers are:
If x = 10
Then the two numbers are:
first number x = 10
second number (40-10) = 30
If x = 30
Then the two numbers are:
first number = 30
second number (x-30) = 10
Even if interchanged, the two numbers are 10 and 30
To check:
10 + 30 = 40
(10) (30) = 300