Answered

4 number have a total of 92.The first # is twice the 2nd # and the 3rd # is 4 more than the sum of the first two. The 4th# is 3 less than the difference of the first 2 numbers.What are the numbers?

Sagot :

Let x be the second number.

Representation:
      First number = 2x  (twice the second number)
      Second number = x
      Third number = (2x+x) + 4 (four more than the sum of the first two numbers)
      Fourth number = (2x-x) - 3  (three less than the difference of first two numbers)
      Total of the four numbers = 92

Equation:
    2x + x + (2x+x+4) + (2x-x-3) = 92
   2x + x + 3x + 4 + x-3 = 92

Combine the like terms:
   2x + x + 3x + x + 4 - 3 = 92
   7x +1 = 92
   7x = 92-1
   7x = 91
   7        7
   x = 13 

The numbers are:
  first number = 2x  
                        = 2(13)
                        = 26

   second number = x
                                = 13

   third number =  2x + x + 4
                           = 2 (13) + 13 + 4
                           = 26 + 13 + 4
                           = 43
 
   fourth number =  2x-x-3
                             = 2(13) - 13 - 3
                             = 26 - 13- 3
                              = 10

To check:
     26 + 13 + 43 + 10 = 92
                                 92 = 92    



   

ID Other Questions