Answered

The 4 oldest people in golden city live on total of 384 years put together.The difference in age for the youngest and the second oldest is 14 years.The second youngest is 3 years older than the youngest.The oldest is older 20 years than the average of the second oldest and the youngest.What are their ages?.

Sagot :


Let   youngest = x

     2nd youngest =  x + 3 

     2nd oldest = x + 14

     oldest = 20 + (x + x + 14)   
                            2
               =  20 + (2x+14)
                              2
               = 20 + x + 7
               = x + 27

     Total of their ages = 384

Equation:
    (x) + (x+3) + (x+14) + (x+27) = 384
    4x + 44 = 384    
    4x = 384 - 44
    4x = 340
     4       4
    x = 85

Their ages if x = 85
Youngest: x     85 yrs. old

2nd youngest : x + 3
                      85 + 3 = 88 years old

2nd oldest:  x + 14
                  85 + 14 = 99 years old

Oldest:  x + 27
            85 + 27 = 112 years old

To check:
85 + 88 + 99 + 112 = 384
                      384 = 384