Alden is three years older than Yaya
Dub. The product of their ages is
460. Determine their ages.
Let x age of Yaya Dub
x + 3 age of Alden
460 product of their ages
Equation:
(x)
(x + 3) = 460
x²
+ 3x = 460
x²
+ 3x - 460 = 0 Product (Special Product/Quadratic Trinomial)
Solve by factoring:
(x
- 20) (x+23) = 0 Factor
Solve for x:
x-20 = 0
x+23 = 0
x1 = 20 x2
= -23
Choose the positive x-value: x1
= 20
Determine their ages: Substitute 20 for x
Age of Yaya Dub: x = 20 Age of
Alden: x + 3
(20)
+ 3 = 23