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suppose q varies inveresely as the square of r. What happens if r is multiplied by 1/8?

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Kaiusid
We write the equation: qr^2 = k. If we multiply r by (1/8), we get: q (1/8r)^2 = k --> q (1/64)(r^2) = k. Therefore, the proportionality constant k, increases 64 times its original value.