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A rectangular lot has an area of 240m². What are the dimensions of the lot if it requires 64m of fencing materials to enclose it?

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Kaiusid
let A be the length and B be the width. We write: AB = 240 and 2A + 2B = 64. Evaluating the equations, we get: A = 240/B and A + B = 32 --> (240/B) + B = 32 --> (B)[(240/B) + B = 32] --> 240 + B^2 = 32B --> B = 12, 20. The dimensions: 12 m x 20 cm