Sagot :
the son is 10 yrs old and the father is 40 yrs old..
solution
let m = age of the son
4m = 20 +2m
4m- 2m =20
2m = 20 gcf 2.. divide both by 2
m= 20
therefore the son is 10 yrs old
solution
let m = age of the son
4m = 20 +2m
4m- 2m =20
2m = 20 gcf 2.. divide both by 2
m= 20
therefore the son is 10 yrs old
A father is 4 time as old as his son. In 20 years, the father will be twice as old as his son. Find the present age of each.
R: Let x = Son's age
4x = Father's age
Present In 20 years
Son x x + 20
Father 4x 4x + 20
E: 4x + 20 = 2(x + 20)
S: 4x + 20 = 2(x + 20)
4x + 20 = 2x + 40
4x - 2x = 40 - 20
[tex] \frac{2x}{2} = \frac{20}{2} [/tex]
x = 10; 4x = 40
A: The son is 10 years old while his father is 40 years old.
C: 4x + 20 = 2(x + 20)
4(10) + 20 = 2(x + 20)
40 + 20 = 2(10 + 20)
60 = 60 (Equal meaning correct)
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:)
R: Let x = Son's age
4x = Father's age
Present In 20 years
Son x x + 20
Father 4x 4x + 20
E: 4x + 20 = 2(x + 20)
S: 4x + 20 = 2(x + 20)
4x + 20 = 2x + 40
4x - 2x = 40 - 20
[tex] \frac{2x}{2} = \frac{20}{2} [/tex]
x = 10; 4x = 40
A: The son is 10 years old while his father is 40 years old.
C: 4x + 20 = 2(x + 20)
4(10) + 20 = 2(x + 20)
40 + 20 = 2(10 + 20)
60 = 60 (Equal meaning correct)
--
:)