A househelp recieves a salary of P48,000.00 a year with a contract of P200.00 annual increase for 8 years.What is his total income for 8 years?
PROCESS:
a1=P48,000 , d=P200 , n=8 , S8=?
Sn=n/2(2a1+(n-1)d)
S8=8/2(2(48,000)+(8-1)200)
S8=4(96,000+7(200)
S8=4(96,000+1,400)
S8=4(97,400)
S8=389,600
So, the total salary for 8 years is P389,600.00
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