Lollisujjid
Answered

a force of 600N is applied across a 40kg box. the frictional force acting on the box is 200N
a. what is the net horizontal force of the box?
b. calculate the acceleration of the box.
c. how far will the box travel after 12 seconds if it continues to accelerate at this rate starting from rest

sana masagot niyo:)​

Sagot :

Januarilorehuela613id

Answer:

a. the friction force exerted is 0N a/c to the newtons 3rd law of motion

b.Static friction coefficient × weight of the box=6N

c.Monkey must apply horizontal force slightly more than the magnitude of the frictional force to start the motion

i.e. 40N x coefficient of static friction (0.40) = 16N

Explanation:

pa follow tysm

Sana maka tulong

correct me if I'm wrong

Januarilorehuela613id

Answer:

a. the friction force exerted is 0N a/c to the newtons 3rd law of motion

b.Static friction coefficient × weight of the box=6N

c.Monkey must apply horizontal force slightly more than the magnitude of the frictional force to start the motion

i.e. 40N x coefficient of static friction (0.40) = 16N

Explanation:

pa follow tysm

Sana maka tulong

correct me if I'm wrong

ID Other Questions