let 'a' be the length of one side of the larger square
let 'b' be the length of one side of the smaller square
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since we are given that the side length of one lot is 2 meters less than the other then we can have the equation as
b = a - 2 ------equation 1
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Given that the area of the larger square is 44 square meters greater than that of the smaller then we'll have
a² - b² = 44 ----equation 2
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substitute equation 1 to equation 2
a² - (a-2)² = 44
simplify
a² - (a² - 4a + 4) = 44
a² - a² + 4a - 4 = 44
4a = 44 + 4
4a = 48
a = 12 m
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substitute the value of 'a' to equation 1
b = a - 2
b = 12 - 2
b = 10m
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therefore we can say that the smaller square measures 10 x 10 m and the larger square measures 12 x 12 m
