y is equal to positive negative one, and x is equal to negative 1
[tex] y^{2} [/tex] + 5x = 4 and [tex] y^{2} [/tex] -3x -4
multiply negative to the second equation, so as to cancel the y squared, then you will have :
[tex] y^{2} [/tex] + 5x = 4 and -[tex] y^{2} [/tex] +3x +4
simply add them, giving you:
8x+8=0, solve for x, giving you -1
substitute -1 to the x of any equation, solve for it, then y= positive negative 1
