Answer:
(bq+2x)(bq-2x+3) = b^2q^2+3bq-4x^2+6x
Step-by-step explanation:
(bq+2x)(bq-2x+3)
= (bq)(bq) + (bq)(-2x) + (bq)(3) + (2x)(bq) + (2x)(-2x) + (2x)(3) =
= b^2q^2 - 2bqx + 3bq +2bqx - 4x^2 + 6x
= b^2q^2 +3bq - 4x^2 + 6x
I hope it helps
Correct me if I'm wrong
