Seankennbelmonteid
Answered

if the area of the takraw court is 880 square feet and its length is 4 feet longer than twice its width,what are the dimensions of the court?​

Sagot :

Kailan32id

Answer:

W= 3.69 feet

L = 4 + 2W = 11.38  feet

Step-by-step explanation:

Let L = length   ,   W = width (all in feet)

 

L = 4 + 2 W

Area = 42 = L x W = ( 4 + 2W ) x  W

 

42=  4W + 2W(W) = 4W + 2W^2

 

or 2W^2 + 4W -42 = 0

#LetsStudy