Activity 2: MY PERFECT MATCH IS YOU!

Instruction: Find the perfect match of the given arbitrary constants in column A to its corresponding Quadratic equation in column B. Transform first the equation in standard form if needed. Write only the letter of your choice on a separate sheet of paper.​


Activity 2 MY PERFECT MATCH IS YOUInstruction Find The Perfect Match Of The Given Arbitrary Constants In Column A To Its Corresponding Quadratic Equation In Col class=

Sagot :

Answer:

  1. E
  2. A
  3. N
  4. T
  5. C
  6. S
  7. M
  8. I
  9. H
  10. K

Step-by-step explanation:

M:

y² + y = -1

y² + y + 1 = 0

a = 1 , b = 1 , c = 1 (1)

A:

x² + 4x - 2 = 0

a = 1 , b = 4 , c = -2 (2)

T:

5(x² - x) = -3x² + 8

5x² - 5x = -3x² + 8

5x² - 5x + 3x² - 8 = 0

8x² - 5x - 8 = 0

a = 8 , b = -5 , c = -8 (4)

H:

2m² + 5m - 7 = -3m² - 7m + 10

2m² + 5m - 7 + 3m² + 7m -10 = 0

5m² + 12m - 17 = 0

a = 5 , b = 12 , c = -17 (9)

E:

5x - 2x² = -8

5x - 2x² + 8 = 0

-2x² + 5x + 8 = 0

a = -2 , b = 5 , c = 8 (1)

N:

7p² - p = 0

a = 7 , b = -1 , c = 0 (3)

I:

2k(-3k + 5) - 7 = 5k

-6k² + 10k - 7 - 5k = 0

-6k² + 5k - 7 = 0

a = -6 , b = 5 , c = -7 (8)

C:

(4c - 3)(c + 2) = 3

4c² + 8c - 3c - 6 - 3 = 0

4c² + 5c - 9 = 0

a = 4 , b = 5 , c = -9 (5)

K:

y + 1 -2y² = 0

-2y² + y + 1 = 0

a = -2 , b = 1 , c = 1 (10)

S:

3(x + 3) - 4x² = 3x²

3x + 9 - 4x² - 3x² = 0

3x + 9 - 7x² = 0

-7x² + 3x + 9 = 0

a = -7 , b = 3 , c = 9 (6)