A 0.300-kg stone that is initially station is kicked with a horizontal force of 10.0 n that made it cover a distance of 0.3 m

Sagot :

[tex]\tt{\huge{\blue{Explanation:}}}[/tex]

The work done by an object exerting a force F at a distance d is given by

[tex]\boxed{W = Fd}[/tex]

where:

W = work

F = force

d = distance

[tex]\tt{\huge{\red{Solution:}}}[/tex]

Solving for W

W = Fd

W = (10.0 N)(0.3 m)

[tex]\boxed{W = \text{3 J}}[/tex]

Therefore, the work done is 3 J.

[tex]\\[/tex]

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