A 1580Nm of work was done on an object in 35 seconds. How much power is required?​

Sagot :

[tex]\tt{\huge{\blue{Explanation:}}}[/tex]

The power of an object doing a work W in a given time t is given by

[tex]\boxed{P = \frac{W}{t}}[/tex]

where:

P = power

W = work

t = time

[tex]\tt{\huge{\red{Solution:}}}[/tex]

Solving for P

[tex]P = \dfrac{W}{t}[/tex]

[tex]P = \dfrac{\text{1580 Nm}}{\text{35 s}}[/tex]

[tex]\boxed{P = \text{45.14 W}}[/tex]

Therefore, the power required is 45.14 W.

[tex]\\[/tex]

#CarryOnLearning