(x+1)²
first term = x²
second term = 2x
last term = 1
⇨ (x²+2x+1)
(x+2)²
first term = x²
second term = 4x
last term = 4
⇨ (x²+4x+4)
(x+3)²
first term = x²
second term = 6x
last term = 9
⇨ (x²+6x+9)
(x+y)²
first term = x²
second term = 2xy
last term = y²
⇨(x²+2xy+y²)
you can also use the foil method
ex) (x+1)² = (x+1)(x+1)
f = the first term (x)(x) = x²
o = outer term (x)(1) = x
i = inner term (1)(x) = x
l = last term (1)(1) = 1
copy the first term, add the outer and inner term and copy also the last term so the answer is (x²+2x+1)
hope you understand my explanations.. i'm not good in explaining because i'm not a teacher..(^_^) AMEN AND GODBLESS YOU TOO AND YOUR FAMILY..