Leeyoungid
Answered

Three positive numbers for a geometric sequence. If the geometric mean of the first two numbers is 6 and the geometric mean of the last two numbers is 24, find the three numbers and their common ratio.

Sagot :

Leo16id
Let a, 6, b, 24, c be the geometric sequence.

Let a₁= 6 and a₃= 24

Since the 3 numbers are positive, we take r=2

a= 6÷ 2= 3
b= 6 × 2= 12
c= 24 × 2= 48

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