Answered

Solving polynomials

16 -a^2 - 6ax - 9x^2

Sagot :

-9x²-6ax-ax²+16
first, you divide them in negative 1 and it will become
=9x²+6ax+a²-16
2nd, you transpose 16
=9x²+6ax+a²=16
third, factor it (9x²+6ax+a²)
=(3x+a)²=16
then find their square root
√(3x+a)²=√16
3x+a=4⇨answer

i hope it can help..