A compound consists of 36.48 % Na, 25.41 % S, and 38.11 % O. It has a molar mass of 252.10 g/mol. Calculate both empirical and molecular formulas.​

Sagot :

Answer:

SThe empirical formula is calculated as follows

calculate the moles of each element

moles= % composition/molar mass of element

that is iron (Fe) = 53.70/55.86 = 0.96 moles

Sulfur (s)= 46.30/32.07= 1.44 moles

calculate the mole ratio by diving each mole by smallest mole(0.96)

that is Fe = 0.96/0/96 =1

S= 1.44/0/96 = 1.5

multiply by 2 to remove decimal

that is Fe = 1 x 2 =2

S= 1.5 x2 = 3

the empirical formula is therefore = Fe2S3