Redshardid
Answered

Find the values of a, b, and c

Formula to use:
[tex]x= -b \sqrt{b^2-4ac} [/tex]
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2a


[tex]2x+9x=0 \\ 6x-1=2x^2 \\ 2x(x-6)=5 \\ (x-6)(x-9)=0[/tex]

Sagot :

Sungheeid
2x+9x=0
a=2 b=9 c=0

6x-1=2x^2
~ 6x-1-2x^2=0
~ -2x^2+6x-1=0
a= -2 b=6 c= -1

2x(x-6)=5
~2x^2-12x=5
~2x^2-12x-5=0
a= 2 b= -12 c= -5

(x-6) (x-9)=0
~x^2-9x-6x+54=0
~x^2-15x+54=0
a= 1 b= -15 c= 54