ANSWER A.
[tex] \\ \\ [/tex]
[tex] \\ \frac{a}{1} = \frac{b}{2} \\ \\ \boxed{a = \frac{b}{2} } \\ \\ [/tex]
[tex] \\ \frac{c}{3} = \frac{b}{2} \\ \\ \boxed{c = \frac{3b}{2} } \\ \\ [/tex]
Change the variables of (5a-6b-2c)/(x)
[tex] \\ \frac{5( \frac{b}{2} ) - 6b - 2( \frac{3b}{2} )}{x} \\ \\ [/tex]
Multiply
[tex] \\ \frac{ \frac{5b}{2} - 6b - \frac{6b}{2} }{x} \\ \\ [/tex]
Subtract
[tex] \\ \frac{ \frac{ - 13b}{2} }{x} \\ \\ [/tex]
I used trial and error by evaluating x using the given value.
[tex] \\ \frac{ \frac{ - 13b}{2} }{ - 13} \\ \\ [/tex]
Cancel both -13 numerator and denominator
[tex] \\ \boxed{ \frac{b}{2} } \\ \\ [/tex]
Proved that a/1= b/2 = c= 3 = (5a-6b-2c)/x
[tex] \\ \\ \\ [/tex]
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