learning task 1: calculate the mass percent of each element in a compound. write your solution in a seperate sheet of paper.
calculate the percent by mass of each element in the following compunds:
1. methane, CH4(C = 12.01 g/mol; H = 1.008 g/mol)
2. sodium nitrate, NaNO3 (Na = 23.0g/mol; N = 14.0g/ mol; O = 16.0g/mol)

thanks agad.
nonsense-reported

[tex]1.) \: molar \: mass = ( 12.01g \mol \: \times 1) + (1.008g \mol \: \times 4) \\ molar \: mass \: = (16.042g \mol) \\ for \: \%c \\ \%c = \frac{12.01g \mol \times 1}{16.042g \mol} \times 100 \\ \%c = 74.87\% \\ for\%h \: \\ \%h = \frac{1.008g \mol \times 1}{16.042g \mol} \times 100 \\ \%h = 25.13\%[/tex]

[tex]2.)molar \: mass = (23.0g \mol \times 1) + (14.0g \mol\times 1) + (16.0g \mol \times 3) \\ molar \: mass = 85.0g \mol \\ for\%na \\ \%na = \frac{23.0g \mol \times 1}{85.0g \mol} \times 100 \\ \%na = 27.06\% \\ for\%n \: \\ \%n = \frac{14.0g \mol \times 1}{85.0g \mol } \times 100 \\ \%n = 16.47\% \\ for\%o = \frac{16.0g \mol \times 3}{85.0g \mol} \times 100 \\ \%o = 56.47\%[/tex]

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--hope it help

_james㍿