Ellagraceriverid
Answered

a plane starting from rest at one end of a runaway undergoes a constant accelaration of 4.8m/s squered,for 15 seconds before it take off 2.how fast is the plane at take off.

Sagot :

Jeremiaid
Given:
             Initial velocity = 0
             Acceleration = 4.8 m/s
             Time = 15 seconds
Asked: Velocity of the plane at take off or Final velocity
Solution:
 
    Acceleration = [tex] \frac{ v_{f} - v_{i} }{t} [/tex]
     4.8 m/s²     = [tex] \frac{ v_{f}- 0}{15 s} [/tex]
     4.8 m/s² (15 s) = [tex] v_{f} [/tex]
      72 m/s = [tex] v_{f} [/tex]