We are looking for √7084. We should first factor out 7084 by continuous division:
4 | 7084 It is divisible by 4 since the last two digits are divisible by 4
11 | 1771 It is divisible by 11 since the alternating sum is 0
7 | 161
23
So we know √7084 = √(2² x 7 x 11 x 23) = 2√(7 x 11 x 23) = 2√1771
