how many different 3-digit even integers can be formed by arranging the digits in the number 2456 if repetation is not allowed​

Sagot :

Answer:

18

Step-by-step explanation:

  1. 246
  2. 254
  3. 256
  4. 264
  5. 426
  6. 452
  7. 456
  8. 462
  9. 524
  10. 526
  11. 542
  12. 546
  13. 562
  14. 564
  15. 624
  16. 642
  17. 654
  18. 652

48

Step-by-step explanation:

Since we know that even numbers are any numbers that can be exactly divided by 2, in given set of numbers 2, 4, and 6 are even numbers. Now we will gonna find out if how many different 3-digit even integers can be formed.

2x4x6=N

Therefore the total three digit even numbers formed from the digits 2, 4, 5 and 6 such that no repetition of digit is allowed is 48.