20. Using the standard normal curve, what is the approximate area of P(1.63 <Z<2.79)?
[tex](1.63 < z < 2.79)[/tex]


Sagot :

Answer:

Area = 4.89%

Step-by-step explanation:

Please see attached image for my illustration of the graph (normal curve), the Z-table values.  Click to enlarge the image.

Since P(1.63 < z < 2.79), the area is between two z-scores on one side of the mean, here, on right side of the mean, or right-tailed.

Check the values on Z-table following these steps:

a) Split the scores:

  • 1.63 = 1.6 + .03
  • 2.79 = 2.7 + .09

b)  Locate 1.6 on leftmost column, and .06 on topmost row of the Z-table.

c)  Locate the intersection of 1.6 and .03 (column and row).  The intersection is .94845

d) Locate 2.7 on leftmost colums, and .09 on topmost row of the Z table.

e) Locate the intersection of 2.7 and .09 (column and row). The intersection is .99736.

For one side of mean, subtract the smaller value of z-score from the bigger value.

Approximate Area % = (0.99736 - 0.94845) × 100

Approximate Area ≈ (0.04891) × 100

Approximate Area ≈  4.89%

View image Аноним