A number round off to 4000. The digit in the hundred place is twice the digit in the tens place. The sum of the digit is 12.The number uses only two different digit. Find the number..
We let the number be abcd. From the given: b = 2c a+b+c+d = 12 Since we have only two different numbers used we let: a = b, c = d, this would mean: 2b + 2c = 12 2(2c) + 2c = 12 6c = 12 c = 2 b = 4
