Sagot :
The formula is:
[tex]n= \frac{a_n-a_1}{d} +1= \frac{59-3}{4} +1= \frac{56}{4} +1=14+1=15[/tex]
So there are 15 terms.
[tex]n= \frac{a_n-a_1}{d} +1= \frac{59-3}{4} +1= \frac{56}{4} +1=14+1=15[/tex]
So there are 15 terms.
Formula:
[tex] t_{n} = t_{1} + (n-1)d[/tex]
59 = [tex] t_{n} [/tex] - the nth term or could be the last term
3 = [tex] t_{1} [/tex] - the first term
4 = d - the common difference
? = n - the number of terms, the one we are solving for
(Substitute)
[tex] t_{n} = t_{1} + (n-1)d[/tex]
59 = 3 + (n -1) 4
59 = 3 + 4n - 4
59 = 4n -1
59 + 1 = 4n
60 = 4n
60 / 4 = 4n /4
15 = n
So, n = 15.
There are 15 terms in the sequence.
[tex] t_{n} = t_{1} + (n-1)d[/tex]
59 = [tex] t_{n} [/tex] - the nth term or could be the last term
3 = [tex] t_{1} [/tex] - the first term
4 = d - the common difference
? = n - the number of terms, the one we are solving for
(Substitute)
[tex] t_{n} = t_{1} + (n-1)d[/tex]
59 = 3 + (n -1) 4
59 = 3 + 4n - 4
59 = 4n -1
59 + 1 = 4n
60 = 4n
60 / 4 = 4n /4
15 = n
So, n = 15.
There are 15 terms in the sequence.