how to solve (8-3x)(8+3x)?

Sagot :

This is a special product which is the difference of two squares:
(a+b)(a-b) = a² - b²
(8-3x)(8+3x) = 64 - 9x²
As you can see, this expression is related in the form:
        
            (x-y) (x+y) 
The rule states that if an expression is in the form

(x-y) (x+y) 
its answer is:  x² - y²

Solve:
                    (8 - 3x) (8 + 3x) = 64 - 9x²
Check:
              F = 8²
              O = 8 (3x)
              I = 8 (-3x)
              L = (-3x) (3x)
            = 64 + 24x - 24x - 9x²
            = 64 - 9x², Correct