Please rewrite in standard form
1.) 2[tex] x^{2} [/tex] = 5x - 1
2.) 5x = 2[tex] x^{2}[/tex] + 7
3.) (x + 7) (x - 1) = 0

Thanks in advance.. :)

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Math

Answered

Please rewrite in standard form
1.) 2[tex] x^{2} [/tex] = 5x - 1
2.) 5x = 2[tex] x^{2}[/tex] + 7
3.) (x + 7) (x - 1) = 0

Thanks in advance.. :)

Sagot :

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Mlcparra16id Mlcparra16id · Answer 1

Mlcparra16id Mlcparra16id

All we need to do is have 0 in one side.
1) 2x²-5x+1=0 [We transpose all to one side]
2) 0 = 2x²-5x+7 [Do the same as the first]
3) x²+6x-7 = 0 [Simply do FOIL method]

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