Factor 6x^2 + 19x + 3.

Sagot :

We use the quadratic formula:
x = -19 ±√(19²-72) = -19 ± √(361-72) = -19 ± √289 = -19 ± 17 = -1/6 or -3
               12                      12                   12             12
So we have : 
(x+1/6)(x+3)
We multiply the other by 6 since the value of a is 6 [ 6x² ]
So: 6x²+19x+3 = (6x+1)(x+3)