Y varies directly as x and z. Y is equal to 16 when x=2 and z=4, find Y when x=1 and z=7

pahelp please
#ASAP​


Sagot :

A random dude is here to save the day!

Step 1: Recall the formula of joint variation, which is

[tex]y = kxz[/tex]

where y varies directly as x and z.

Step 2: Substitute the first given terms. (y is 16, x is 2, and z is 4)

[tex]16 = k(2)(4)[/tex]

Step 3: Multiply and divide both sides by 8.

[tex]16 = k(8)[/tex]

[tex] \frac{16}{8} = \frac{k(8)}{8} [/tex]

[tex]k = 2[/tex]

Step 4: Substitute the next given terms, with k. (x is 1, z is 7, and k is 2.

[tex]y = (2)(1)(7)[/tex]

[tex]y = 14[/tex]

Therefore y is equal to 14 when x is equal to 1 and z is equal to 7.

Hope this helps you!