AREA
Question: A square side measure [tex]3n^{2}-7[/tex], what is its area?
[tex]A.\:9n^{4}-49[/tex]
[tex]B.\:9n^{4}+49[/tex]
[tex]C.\:9n^{4}-21n^{2}+49[/tex]
[tex]{\boxed{D.\:9n^{4}-42n^{2}+49}}[/tex]
Formula (area of a square):
[tex]A=S^{2}[/tex]
Equation:
[tex]{\tt{(3n^{2}-7)^{2}}}[/tex]
Solution:
[tex]{\tt{(3n^{2}-7)^{2}}}\\{\tt{3n^{2}(3n^{2})=9n^{4}}}\\{\tt{3n^{2}(-7)=-21n^{2}}}\\{\tt{-7(3n^{2})=-21n^{2}}}\\{\tt{-7(-7)=49}}\\{\tt{9n^{4}-21n^{2}-21n^{2}+49}}\\{\boxed{\tt{9n^{4}-42n^{2}+49}}}[/tex]
Answer:
The area of the square is
[tex]{\orange{\boxed{\orange{\huge{\boxed{\sf{9n^{4}-42n^{2}+49}}}}}}}[/tex]
[tex]{\blue{\boxed{ItzyMidzy:))}}}[/tex]
#CarryOnLearning
