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Solve the following systems by substitution: 2x + y = 1
3x + y = 4

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Mlcparra16id
2x + y = 1 ... [1] 
3x + y = 4 ... [2]

[2] - [1]
3x + y = 4
-2x -y = -1
    x = 3

So:
2x + y = 1
2(3) + y = 1
6 + y = 1
y = -5

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