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Solve the following systems of equations by elimination:
4x + 3y = 15
2x – 5y = 1

Sagot :

Mlcparra16id
4x + 3y = 15 ... [1]
2x - 5y = 1 ... [2]

[1] - 2[2]
4x + 3y = 15
-4x +10y = -2
      13y = 13
         y = 1

So:
4x + 3y = 15
4x + 3(1) = 15
4x + 3 = 15
4x = 12
x = 3