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Solve the following systems by elimination: x + y = 2
2x – y = 4

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Mlcparra16id
x + y = 2 ... [1]
2x - y = 4 ... [2]

2[1] - [2]
2x + 2y = 4
-2x +y  = -4
       3y  = 0 
         y  = 0 

So we have y equal to 0 and we substitute the value of y to the first equation:
x + y = 2
x + 0 = 2 
 x= 2