Sagot :
Since the diameter is twice the radius we just divide this in half which is 5m.
[tex]Volume= \pi r^2h=(5m)^2*16m* \pi =400 \pi m^3[/tex]
[tex]Volume= \pi r^2h=(5m)^2*16m* \pi =400 \pi m^3[/tex]
The diameter is always twice the radius so:
10 m=2r
r=5 m
Volume of the cylinder:
V=πr²h
Substitute
V=π(5 m)²(16 m)
V=(16π m)(25 m²)
V=400π m³ or 1,256 m³
Hope this helps =)
10 m=2r
r=5 m
Volume of the cylinder:
V=πr²h
Substitute
V=π(5 m)²(16 m)
V=(16π m)(25 m²)
V=400π m³ or 1,256 m³
Hope this helps =)