[tex]\bold{Solution:} \\ \\ Let\ \bold{x}\ be\ the\ lunch. \\ \\ \bold{Equation:} \\ \\ 4\bold{x}=\ Php\ 159.80 \\ \\ \frac{\not{4}\bold{x}}{\not{4}}= \frac{Php\ 159.80}{4} \\ \\ \boxed{\bold{x=\ Php\ 39.95}} \\ \\ \bold{General\ Conclusion:} \\ .\ \ \ \ \ \ \ The\ value\ of\ each\ lunch\ is\ \bold{\underline{Php\ 39.95}} \\ . \ \ \ \ \ \ \ Therefore,\ the\ answer\ is\ \bold{letter\ \underline{D}}. \\ \\ \\ \bold{Hope\ it\ Helps:)} \\ \bold{Domini}[/tex]
