Boblmc724id
Answered

Find the area of a trapezoid with bases of 42 dm and 34 dm and a height of 29 dm.

Sagot :

Mlcparra16id
[tex]Area= \frac{(b_1+b_2)h}{2} = \frac{(42+34)29}{2} = \frac{(76)29}{2} =38*29=1102dm^2[/tex]
Jers15id
The formula for the area of the trapezoid:
A=0.5h(b1+b2)

substitute with the given measurements
A=0.5(29 dm)(42 dm+34 dm)
A=0.5(29 dm)(76 dm)
A=(29 dm)(38 dm)
A=1,102 dm²

Hope this helps =)