Alonzopongos20id
Answered

Find the area of a triangle with an altitude of 26 dm and a base of 17 dm.

Sagot :

Mlcparra16id
[tex]Area= \frac{base*altitude}{2} = \frac{17*26}{2} = \frac{442}{2} =221dm^2[/tex]
Jers15id
The area of the triangle is:
A=0.5bh
simply the base or the side that is formed with a 90 degree by the altitude.

substitute:
A=0.5(26 dm)(17 dm)
A=(13 dm)(17 dm)
A=221 dm²

Hope this helps =)