Sagot :
The area of the circle is :
[tex] \pi r^2= \pi (3^2)=9 \pi [/tex]
The area of a square is:
[tex]s^2=6^2=36[/tex]
It is obvious that the circle's area is smaller since pi is approximately 3.14 and 36 is equal to 9*4. So the square's area is higher by:
[tex]36-9 \pi =7.72ccm^2[/tex]
[tex] \pi r^2= \pi (3^2)=9 \pi [/tex]
The area of a square is:
[tex]s^2=6^2=36[/tex]
It is obvious that the circle's area is smaller since pi is approximately 3.14 and 36 is equal to 9*4. So the square's area is higher by:
[tex]36-9 \pi =7.72ccm^2[/tex]
Case 1:Circle
Diameter is twice the radius so:
6 cm=2r
r=3 cm
Area of a circle:
A=πr²
A=π(3 cm)²
A=9π cm² or 28.26 cm²
Case 2: Square
The area of the square is:
A=s²
A=(6 cm)²
A=36 cm²
To find how much larger the square is, just subtract
36 cm²-28.26 cm²=7.74 cm²
Hope this helps =)
Diameter is twice the radius so:
6 cm=2r
r=3 cm
Area of a circle:
A=πr²
A=π(3 cm)²
A=9π cm² or 28.26 cm²
Case 2: Square
The area of the square is:
A=s²
A=(6 cm)²
A=36 cm²
To find how much larger the square is, just subtract
36 cm²-28.26 cm²=7.74 cm²
Hope this helps =)