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Ronel is two years older than four times his son's age. Thrèe years from now, the some of their age will be 63. How old is each now?

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Mlcparra16id
Let the age of Ronel now be R and the son's age be S.

We know that:
[tex]R=4S+2[/tex]
and
[tex](R+3)+(S+3)=63 \\ R+S=57[/tex]

We substitute R with 4S+2

[tex]4S+2+S=57 \\ 5S=55 \\ S=11[/tex]

Since the son is 11 then the father is 57-11=46 years old

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