Answered

find the base angle of an isosceles triangle in vertex angle is 48.

Sagot :

Mlcparra16id
The sum of the interior angles of a triangle is 180°
∠A+∠B+∠C=180°

So we already know one angle which is the vertex angle

48°+∠B+∠C=180°
Since ∠B=∠C

2∠B=180°-48°
2∠B=132°
∠B=66°

Therefore the base angles are each equal to 66°