Given:
Price of the electricity = P1.5 per kilowatt-hour
Electric Bulb = device used
Wattage of the Electric Bulb = 25 watts
Range of time used = 8: 00 pm - 5: 00 am in 1 month
Find:
Payment out from the variables.
Solution:
Step 1: We get the wattage of the device used.
Step 2 : We get the number of hours the device was used.
Step 3: We multiply the wattage with the number of hours used.
Step 4: We change the unit to kilo-watt hours.
Step 5: We multiply the result by the price.
Wattage = 25 watts
Number of hours used = 8:00 pm - 5:00 am = 9 hours
( I assumed that 1 month = 30 days)
30 x 9 hours = 270 hours
25 watts x 270 hours = 6, 750 watt-hours
6, 750 watt-hours x [tex] \frac{1 kW}{1000 watts} [/tex] = [tex] \frac{6, 750 watt-hours (kW)}{1,000watt} [/tex] = 6. 75 kWh or 6. 75 kilo-watt hours
6. 75 x P1.5 = P10. 125
Final Answer: P10.125
