[tex]Simplify\ (3x-y)(2x^2-3xy+3y^2) \\ \\ Solution: \\ (3x-y)(2x^2-3xy+3y^2) \\ \\ To\ solve\ the\ equation,\ use\ distributive\ property\ so\ you'll\ like\ this \\ \\ 6x^3-9x^2y+9xy^2 \\ .\ \ \ \ -2x^2y+9xy^2-3y^3 \\ ^{-----------------} \\ 6x^3-11x^2y+18xy^2-3y^3\ \to Get\ the\ sum\ to\ get\ the\ final\ answer. \\ \\ \\ Therefore,\ the\ simplified\ answer\ is\ \underline{6x^3-11x^2y+18xy^2-3y^3}. \\ \\ \\ Hope\ it\ Helps :) \\ Domini[/tex]
