One number is five more than twice another. If their sum is decreased by ten, the result is 22. Find the numbers.
(I'll use RESAC Form).
R : Let x = the number
2x + 5 = another number
E : (x+2x+5) - 10 = 22
S : (x+2x+5) - 10 = 22
3x + 5 - 10 = 22
3x - 5 = 22
[tex] \frac{3x}{3} = \frac{27}{3} [/tex]
x = 9 ; 2x + 5 = 23
A : The numbers are 9 and 23.
C : (x+2x+5) - 10 = 22
9 + 2(9) + 5 - 10 = 22
9 + 18 + 5 - 10 = 22
27 - 5 = 22
22 = 22
