A basketball player is 6 feet 8 inches tall. How far should he stand from a light which is 15 feet above ground, in order to cast a shadow of 25 feet long?
tan α = [tex] \frac{6.67}{25} [/tex] α = 14 degree 56' (sorry, there's no degree symbol here)
Let x be the distance of the basketball player from the light tan 14 degree 56' = [tex] \frac{15}{25 + x} [/tex] 25 + x = [tex] \frac{15}{tan 14 degree 56'} [/tex] 25 + x = 56.22 x = 56.22 - 25 x = 31.22 ft --> answer
