tan B=1/3
do the inverse
B=tan^-1(1/3)
B=18'26'58.2''
tan(a+b)=[tex]\frac{tanA+tanB}{1-tanAtanB}[/tex]
3=[tex]\frac{tanA+(1/3)}{1-(1/3)tanA}[/tex]
Multiply both sides by (1-(1/3)tanA
3-tanA=tanA+(1/3)
3-(1/3)=2tanA
8/3=2tanA
Divide both sides by 2
4/3=tanA
do the inverse
A=tan^-1(4/3)
A=53'7'48.37"
Hope this helps =)
