How much water is contained in a bathtub with a radius of 0.5 meter and a height of 0.6

Sagot :

solve for the volume of the bathtub:
use the formula, V = π x r x r x h  or V = πr^2h  ;
where π = 3.14,   r is the radius, & h  is the height
hence;
     V = 3.14  x  0.5 m  x  0.5 m  x  0.6 m
     V = 0.471 cubic meters
The bathtub contained 0.471 cubic meters.
V=πr²h

if pi π is 3.1416
and r is 0.5
and height is 0.6

then the volume is

(3.14)(0.5)²(0.6)

then it must 0.471 cubic meter